ncert solutions for class 11 physics chapter 2 study rankers

of divisions on circular scale = 1 x 10-3/100 = 1 x 10-5 m E, m, 1 and G denote energy, mass, angular momentum and gravitational constant respectively.Determine the dimensions of El2/m5G2. a = -5/6 b = 1/2 c = 1/3. (c) Speed of vehicle = 18 km/h = 18 x 1000/3600 m/s We hope the NCERT Solutions for Class 11 Physics Chapter 7 System of particles and Rotational Motion help you. Its density is ______g a-n 30r ______kg m⁻⁵. What is the order of precision of an atomic clock? .•. Answer: The order of magnitude of a numerical quantity (N) is the nearest power of 10 to which its value can be written.For example. (a) FPS system If velocity of sound in a gas depends on its elasticity and density, derive the relation for the velocity of sound in a medium by the method of dimensions. Multiple Choice Questions The principle of ‘parallax’ is used in the determination of distances of very distant stars. According to Avagadro’s hypothesis, one mole of hydrogen contains 6.023 x 1023 atoms. As the film is extremely thin, this thickness t may be considered to be the size of one molecule of oleic acid i.e., t is the molecular diameter of oleic acid. Calculate the diameter of Jupiter. = 4/3 x 3.142 x (6.37 x 106)3m3 Also the magnetic moment has the units Am2 so that its dimensions can be written as [AL2] where A stands for the dimensions of the electric current. 1 parsec = 3.08 x 1016 m. Question 4. The maximum percentage error in the measurement of its density is Question 2 .11. Explain. r = 2.1 and Ar = ± 0.5 NCERT Solutions for Class 11-science Physics CBSE, 12 Thermodynamics. (b) A Jet plane moves with a speed greater than that of a super fast train. (b) 1 m =………… ly Explain this statement clearly: A LASER is source of very intense, monochromatic, and unidirectional beam of light. Question 2. a=0,b=+(1/2) and c=+(1/2). V ) = (1.37 – 0.01) x (4.11 – 0.01) x (2.56 – 0.01) cm3 = (1.36 x 4.10 x 2.55) cm3 = 14.22 cm3 It is known that the period T of a magnet of magnetic moment M vibrating in a uniform magnetic field of intensity B depends upon M, B and I where I is the moment of inertia of the magnet about its axis of oscillations. }}\end{array}\) In terms of the new unit length, Answer: Question 10. In the evening Suresh inquired all about it. How much parallax would this star (named Alpha Centauri) show when viewed from two locations of the Earth six months apart in its orbit around the Sun? The ratio is very large. 17. Answer: Question 2. The dimensions of diffusion constant D are The radius of curvature of a concave mirror, measured by a spherometer is given by R=l2/6h +h/2 Answer: The values of different fundamental constants are given below: Answer: LASER stands for ‘Light Amplification by Stimulated Emission of Radiation’. A great physicist of this century (P.A.M. Dirac) loved playing with numerical values of fundamental constants of nature. length (1) = 5.12 cm Do you think this relation can be correct? A new unit of length is chosen such that the speed of light in vacuum is unity. = 2 x 22/7 x 2 x 10 (10 x 10 + 2 x 10) mm2 = 1.5 x 104 mm2 Hence, answer is 1.5 x 104. A student derives the following relation between θ and v: tanθ = v and checks that the relation has a correct limit: as v—>θ, θ —>0, as expected. Get answers of your textbook. However, most of the students of class 11 are weak in psychics. It is on account of the fact that in solid phase atoms are tightly packed and so the atomic mass density is close to the mass density of solid. Thickness of hair =3.5 mm/100 = 0.035 mm. Question 16. Here you can get complete NCERT Solutions for Class 11 Physics Chapter 2 Units And Measurement in one place. 4.29 light years =4.508 x 1016/3.80 x 1016 = 1.318 parsec = 1.32 parsec. The radius has three significant figures and the density has four. By using the method of dimension, check the accuracy of the following formula: T =rhρg/2cos θ , where T is the surface tension, h is the height of the liquid in a capillary tube, p is the density of the liquid, g is the acceleration due to gravity, 6 is the angle of contact, and r is the radius of the capillary tube. V = l x w x h You can download the NCERT Book for Class 11 Physics in PDF format for free. Answer: (a) 1 (b) 3 (c) 4 (d) 4 (e) 4 (f) 4. Answer: Given M = 2 x 1030 kg, r = 7 x 108 m The SI units of magnetic field is =6.34 x 10-12 s Answer:  Given that l = 4 cm and Al = 0.1 cm (least count of the metre scale) here l is the distance between the legs of the spherometer. Long Answer Type Questions Volume of Sun = 4/3πr3 x 3.14 x (7 x 108)3  = 1.437 x 1027 m3 It is a well known fact that during a total solar eclipse the disk of the Moon almost completely covers the disk of the Sun. Question 3. Answer: Question 22. 8. Question 19. Lightly sprinkle lycopodium powder on water surface. Answer: From examples 2.3 and 2.4, we get θ = 1920″ and S = 3.8452 x 108 m. During the total solar eclipse, the disc of the moon completely covers the disc of the sun, so the angular diameter of both the sun and the moon must be equal. \(\mathrm{I} \mathrm{m}=\frac{1}{\beta}=\beta^{-1} \text { or } \mathrm{Im}^{2}=\beta^{-2}\) Angular diameter of the moon, θ= Angular diameter of the sun we have a + b + c = 0 Since, in this case significant figures in one quantity (3.00 x 108 ms–1) are 3 and the significant figures in the other quantity (3.154 x 107 s) are 4, therefore, the final result should have 3 significant figures. A boy recalls the relation almost correctly but forgets where to put the constant c. He writes: N=-D n2-n1/x2-x1 This solution provides appropriate answers to the questions provided in the textbook. Name four units used in the measurement of extremely short distances. "To call a dimensional quantity 'large' or is meaningless without specifying a standard for comparison". .•. Question 2. Which of the following is the most precise device for measuring length: This solution contains questions, answers, images, explanations of the complete chapter 2 titled Of Units And Measurement taught in Class 11. r = r0 A1/3 Calorie = \(4.2(1 \mathrm{a}-1)(1 \beta-2)(1 \mathrm{y} 2)=4.2 \mathrm{a}-1 \beta-2 \mathrm{y}^2\). Free PDF download of NCERT Solutions for Class 11 Physics Chapter 3 - Motion in a Straight Line solved by Expert Teachers as per NCERT (CBSE) textbook guidelines. Class 11, Physics chapter 2, Units And Measurement solutions are given below in PDF format. (b) Difference of mass = 2.17 – 2.15 = 0.02 g Answer: [M L2 T-2]. Question 8. Dimensions of L.H.S. Question 4. A body travels uniformly a distance of (13.8 ± 0.2) m in a time (4.0 ± 0.3) s. What is the velocity of the body within error limits? = 6.96 x 102 kg m-3 = 0.7 x 10-3 kg m-3 =1426.731 x 103 = 1.43 x 108 m. Question 2. v = kma rb gc where k is a dimensionless constant and a, b and c are the unknown powers. If you have any query regarding NCERT Solutions for Class 11 Physics Chapter 7 System of particles and Rotational Motion, drop a comment below and we will get back to you at the earliest. Answer:  In order to find out the accuracy of the given equation we shall compare the dimensions of T and rh ρg/2cos θ. III. The dimensions of energy per unit volume are the same as those of Question 24. So, the nuclear mass density is nearly 50 million times more than the atomic mass density for a sodium atom. 31. He makes 20 observations and finds that the average width of the hair in the field of view of the microscope is 3.5 mm. 2. What do you mean by order of magnitude? Answer:  —> Stress and Young’s modulus. 4.29 light years = 4.29 x 9.46 x 1015 = 4.058 x 1016 m So, the new unit of length is } 3 \times 10^{8} \mathrm{m} \text { . }} . Ncert Solutions For Class 11 Physics Download Pdf, ncert solutions for Class 11 physics download pdf . [Energy] = [M L2 T-2], hence 1 joule = 1 kg x 1 m2 x 1 s-2 = 1 kg m2 s-2. In terms of the new unit length, Two gold pieces of masses 20.15 g and 20.17 g are added to the box. From dimensional considerations, find a possible relation for the frequency of a tuning fork. Answer: Question 2. Find the value of 60 W on a system having 100 g, 20 cm and 1 minute as the fundamental units. Mass of nucleus = A An experiment measured quantities a, b, c and then x is calculated by using the relation ab2x =ab2/c3. A new unit of length is chosen such that the speed of light in vacuum is unity. 18. It will help you stay updated with relevant study material to help you top your class! Question 4. where n1 and n2 are number of particles per unit volume for the value of x1 and x2 =55.4 cm2, Question 2. The density of the block is given by, VI. If no, name four physical quantities which are dimensionless. Answer: \(\mathrm{But}, 1 \mathrm{cm} 3=1 \mathrm{cm} \times 1 \mathrm{cm} \times 1 \mathrm{cm}=\left(\frac{1}{100}\right) \mathrm{m} \times\left(\frac{1}{100}\right) \mathrm{m} \times\left(\frac{1}{100}\right) \mathrm{m}\) Answer: Question 14. Question 22. (d) The air inside this room contains more number of molecules than in one mole of air. CBSE NCERT Class 11 Physics Chapter 15 Waves further teaches that mechanical waves can be transverse or longitudinal depending on the relationship between the directions of disturbance or displacement in the medium and that of the propagation of the wave. The baseline AB is the line joining the Earth’s two locations six months apart in its orbit around the Sun. \(\mathrm{But}, 1 \mathrm{cm} 3=1 \mathrm{cm} \times 1 \mathrm{cm} \times 1 \mathrm{cm}=\left(\frac{1}{100}\right) \mathrm{m} \times\left(\frac{1}{100}\right) \mathrm{m} \times\left(\frac{1}{100}\right) \mathrm{m}\) (i) charge on electron (e), (ii) permittivity of free space (ε0), (iii) mass of electron (me), (iv) mass of proton (me) (v) speed of light (c), (vi) universal gravitational constant (G). distance between Sun and Earth = 500 new units. [Y] = [ML-1T–2] Answer: According to the principle of homogeneity of dimensions. Why is a set of 100 measurements of the diameter expected to yield a more reliable estimate than a set of 5 measurements only? Students who are preparing for their Class 11 Physics exams must go through NCERT Solutions for Class 11 Physics Physics Chapter 2 Units and Measurements. Suppose we employ a system of units in which the unit of mass equals a kg, the unit of length equals j8 m, the. These properties of a laser light can be exploited to measure long distances. Answer: The measured (nominal) volume of the block is, }}\end{array}\) 1. Calculate the distance of the star from the earth. Hence, mass of the earth = 5.97 x 1024  kg. \(\begin{array}{l}{1 \mathrm{s}=\frac{1}{\gamma}=\gamma^{-1}} \\ {1 \mathrm{s}^{2}=\gamma^{-2}} \\ {1 \mathrm{s}^{-2}=\gamma^{2}}\end{array}\) Answer:  Here speed of sound in water v = 1450 m s-1 and time of echo t = 77.0 s. Question 23. = 423.4 cm2. Now. The diameter of the moon, D = θ x S Question 2. (a) weber per metre2 (b) newton per coulomb per (metre per second) If you are one of these students, you may […] Answer: Here area of the house on slide = 1.75 cm2 = 1.75 x 10-4 m2 and area of the house of projector-screen = 1.55 m2 It means, distance is measured in foot, mass in pound and time in seconds whereas in India it is MKS system. Further, it was a very large number, its magnitude being close to the present estimate on the age of the universe (-15 billion years). Across Sketch the cross section of soil and label the various layers. – 2c = – 1 …(Hi) Answer: Here, θ=2000 If A be the base area of the boat, then volume of water displaced by boat, V1 = Ad2 = 1.45 x 109m. =>t=nV/400S V = 6.023 x 1023 x –4/3 x 3.14 x (2.5 x 10-10)3 m3 and mass of one mole atom of sodium, M = 23 g = 23 x 10-3 kg \(\begin{array}{l}{\text { (b) The total surface area of a cylinder of radius } r \text { and height } h \text { is }} \\ {S=2 \pi r(r+h)} \\ {\text { Given that, }} \\ {r=2 \mathrm{cm}=2 \times 1 \mathrm{cm}=2 \times 10 \mathrm{mm}=20 \mathrm{mm}} \\ {h=10 \mathrm{cm}=10 \times 10 \mathrm{mm}=100 \mathrm{mm}} \\ {\therefore S=2 \times 3.14 \times 20 \times(20+100)=15072=1.5 \times 104 \mathrm{mm} 2}\end{array}\) Answer: We are given that Question 1. (a) M°L T2 (Ib) M°L2 T-4 (c) M°L T3 (d) M°L2T3 To get fastest exam alerts and government job alerts in India, join our Telegram channel. Find the Young’s modulus of the material of the wire from this data. The number of particles crossing per unit area perpendicular to x-axis in unit time N is given by N= -D(n2-n1/x2-x1), where n1 and n2 are the number of particles per unit volume at x1 and x2 respectively. Answer: 6.67 x 10-8 dyne cm2 g-2 = 6.67 x 1011 Nm2 /kg2 . NCERT Solutions for Class 11. Answer: According to principle of homogenity of dimensional equations, 11.3 g/cm³ = 11.3 x 10. kg/m³, Ans : \(\begin{aligned}(a) 1 \mathrm{kg} \mathrm{m}^{2} \mathrm{s}^{-2} &=\frac{1 \mathrm{kg} \mathrm{m}^{2}}{s^{2}}=\frac{1 \times 1000 \times\left(10^{2}\right)^{2}}{s^{2}} \mathrm{g} \mathrm{cm}^{2} \\ &=10^{7} \mathrm{g} \mathrm{cm}^{2} \mathrm{s}^{-2} \end{aligned}\) Obtain the dimensions of relative density. We have to try to make permutations and combinations of the universal constants and see if there can be any such combination whose dimensions come out to be the dimensions of time. Hence the accuracy is increased. When a beam of parallel light is incident on the prism, find the range of experimental value of refractive index ‘μ’. Thus, the correct value of one light year = 9.46 x 1015 m. Question 9. Give the area and volume of the sheet to correct significant figures. = 7.4 x 1010 m. Question 4. Accuracy of 1 part in 1011 to 1012. Find the value of the gas constant R. Question 1. They ensure a smooth and easy knowledge of advanced concepts. km h-2 Question 10. Answer: RADAR stands for ‘Radio detection and ranging’. We hope the NCERT Solutions for Class 11 Physics Chapter 2 Units and Measurements help you. NCERT Solutions for Class 11 Physics Chapter 13 come with elaborate explanations and precise answers on crucial concepts that students need to have a solid understanding of, in order to clear their entrance exams with an excellent score. }}\end{array}\) 25. .•. V(max) = (1.37 + 0.01) x (4.11 + 0.01) x (2.56 + 0.01) cm3 = (1.38 x 4.12 x 2.57) cm3 = 14.61 cm3 One such combination is: QUESTIONS BASED ON SUPPLEMENTARY CONTENTS, Question 1. Note in Eqn. What is the distance between the Sun and the Earth in terms of the new unit if light takes 8 min and 20 s to cover this distance? A force of (2500 ±5) N is applied over an area of (0.32 ± 0.02) m2. \\ {\therefore \text { distance between Sun and Earth }=500 \text { new units. Chapter 2 Units And Measurement Download in pdf . As the error lies in first decimal place, the answer should be rounded off to first decimal place. = 0.97 x 103 kg m-3 Finally the magnetic field vector B has the units newton (per ampere metre) so that its dimensions can be written as. This is 0.20 cm3 higher than the measured value. unknowns. \(\begin{array}{l}{\text { Therefore, distance can be obtained using the relation: }} \\ {\text { Distance }=\text { Speed } \times \text { Time }=5 \times 1=5 \mathrm{m}} \\ {\text { Hence, the vehicle covers } 5 \mathrm{m} \text { in } 1 \mathrm{s} \text { . (a) The volume of a cube of side 1 cm is equal to…………m3. Mass of earth = — x 3.142 x (6.37 x 106)3 x 5.517 x 103 kg Experiments show that the frequency (n) of a tuning fork depends upon the length (l) of the prong, the density (d) and Young’s modulus (Y) of its material. NCERT Solutions for Class 11 Humanities Subjects. (e) the number of air molecules in your classroom. Show that a calorie has a magnitude \(4.2^{\alpha-1 \beta-2 \mathrm{y} 2}\)in terms of the new units. .•. If n be the number of turns of the coil and l be the length of the coil, then the length occupied by each single turn i.e., the thickness of the thread = 1/n . If d be the distance of Moon from the earth, the time taken by laser signal to return after reflection at the Moon’s surface. .’. Again working with lasers we require length measurements to an angstrom unit (1 A° = 10-10m) or even a fraction of it. The density is accurate only up to three significant figures which is the accuracy of the least accurate factor, namely, the radius of the earth. A calorie is a unit of heat or energy and it equals about 4.2 J where 1 J = 1 kgm2 s-2. Answer:  As the Reynold’s number NR depends on density p, average speed v and coefficient of viscosity η, then let us say, Question 11. ft is required to find the volume of a rectangular Mock. Think of ways by which you can estimate the following (where an estimate is difficult to obtain, try to get an upper bound on the quantity): Fill in the blanks II. = 3.09 x 1016 m = 3 x 1016 m. Question 2. (e) a proton is much more massive than an electron Answer: As relative density is defined as the ratio of the density of given substance and the density of standard distance (water), it is a dimensionless quantity. Also, wherever you can, give a quantitative idea of the precision needed. = 22.4 litre = 22.4 x 10-3 m3 If its coincidence with the age of the universe were significant, what would this imply for the constancy of fundamental constants? Answer:  We know that speed of laser light, c = 3 x 108m/ s Time of echo, t = 8.2 minutes = 8.2 x 60 seconds (ii) How many unit system are there? A famous relation in physics relates ‘moving mass’ m to the ‘rest mass’ m0 of a particle in terms of its speed v and the speed of light c. (This relation first arose as a consequence of special relativity due to Albert Einstein). What is the dimensional formula for torque? V = V2-V1 = A(d2 -d1) As a result, the nearby trees and other objects appear to run in a direction opposite to the train’s motion. Answer: 1 micron (1 p) = 10-6 m Just as precise measurements are necessary in science, it is equally important to be able to make rough estimates of quantities using rudimentary ideas and common observations. Question 2. Question 2. ... Notes Of Ch 2 Units And Measurements Class 11th Physics by studyrankers.com. 5. \(1\mathrm{g} / \mathrm{cm}^ 3=\frac{10^{-3}}{10^{-6}} \mathrm{kg} / \mathrm{m}^{3}=10^{3} \mathrm{kg} / \mathrm{m}^{3}\) And selecting the correct study material and study tools will have a huge impact on the student’s result and academic performance. .•. Question 12. θ=D/d }}\end{array}\) = 25.2 x 16.8 Mass density of Sun is in the range of mass densities of solids/liquids and not gases. Question 2. To determine acceleration due to gravity, the time of 20 oscillations of a simple pendulum of length 100 cm was observed to be 40 s. Calculate the value of g and maximum percentage error in the measured value of g. Here on AglaSem Schools, you can access to NCERT Book Solutions in free pdf for Physics for Class 11 so that you can refer them as and when required. Reynold’s number NR (a dimensionless quantity) determines the condition of laminar flow of a viscous liquid through a pipe. Question 2. Answer: Question 15. (b) Surface area = 2πrh + 2πr2 = 2πr (h + r) Question 2. respectively. m in 1 s. Answer: Question 2. = (1.37 x 4.11 x 2.56) cm3 = 14.41 cm3 -2 a-2 c = 1 Mass of the block (m) = 39.3 g The density of sodium in its crystalline phase = 970 kg m-3 = 4/3 x 3.14 x (0.5 x 10-10) m3 = 5.23 x 10-31 m3 (b) A Jet plane moves with a speed greater than that of a super fast train. Now, [V] = [LT–1], [A] = [LT–2] and [F] = [MLT–2] The number of hair on the head is clearly the ratio of the area of head to the cross-sectional area of a hair. Experimentally, molecular diameter of oleic acid is found to be of the order of 10-9 m. Question 5. Check if your guess is correct from the following data: mass of the Sun = 2.0 x 1030 kg, radius of the Sun = 7.0 x 108 m. When the planet Jupiter is at a distance of 824.7 million kilometres from the Earth, its angular diameter is measured to be 35.72″ of arc. (d) G = 6.67 x 10-11 N m2 (kg)-2 = …. Question 13. =4/3 x 22/7 (0.5 x 10-10)3 m3 (d) Relative density of a substance is given by the relation, Answer: (a) The average rainfall of nearly 100 cm or 1 m is recorded by meteorologists, during Monsoon, in India. If you are a student of Class 11 who is using NCERT Textbook to study Physics, then you must come across chapter 2 Units And Measurement After you have studied lesson, you must be looking for answers of its questions. Answer:  Fundamental physical quantities are those quantities which are independent of each other. \(\begin{array}{l}{\text { Distance between Sun and Earth }} \\ {=\text { Speed of light in vacuum } x \text { time taken by light to travel from Sim to Earth }=3 \times 10^{8} \mathrm{m} / \mathrm{s} \times 8} \\ {\min 20 \mathrm{s}=3 \times 10^{8} \mathrm{m} / \mathrm{s} \times 500 \mathrm{s}=500 \times 3 \times 10^{8} \mathrm{m} \text { . }} Dimensions of both sides of equation ( I ), we get, Question 1 possible relation for the of! By using the relation ab2x =ab2/c3 of by schools.aglasem.com say N ) of the new unit of length }. The frequency of a rectangular sheet of metal were measured with the help of a sphere is measured Vernier. Called derived Units our solar system is 4.29 light years = 4.29 x 9.46 x =... Study NCERT text Book one hour per day for seven days are moving, these distant objects seem move. Youtube channel so that you can also download here the NCERT Solutions for 11! Poisson ’ s ratio and Strain are four examples of dimensionless quantities or 55.8 km means distance. Used these Units in India [ r0 A1/3 ] 3 = 4/3 π [ r0 A1/3 ] =... Value of density is clearly the ratio of molar volume to the train ’ equator... ± 0.02 ) m2 and Rotational Motion help you of dimensional equations, dimensions of both sides equation! 4/3 πr03A mass of Jupiter is very large compared to that of a is... Statement clearly: '' to call a dimensional quantity 'large ' or is meaningless without specifying a standard for ''. And the atomic mass of earth to correct significant figures relative density of is! Complete NCERT Solutions for Class 11 Physics Chapter 2 Units and Measurement, Physics,,. At least six physical quantities which are independent of mass i.e., 365 days = x. This solution provides appropriate answers to the right such that the balloon drifts to position b in 1.... Text Book one hour per day for seven days the refractive index μ! C. answer: about 1 a. ) line joining the earth would not clearly be distinguished as.! Detection and ranging ) uses ultrasonic Waves to detect and locate objects under water Units! Acid in alcohol the atomic volume in m3 of a pin ( we are assuming there is strong... And Measurement – here are all the Solutions of Thermodynamics - Physics explained in detail by experts …. Based on SUPPLEMENTARY CONTENTS, Question 1 of Extremely Short distances years x! 200 divisions on the astronomical scale also check out NCERT Solutions for Class 11 Physics in PDF one per... Circle of radius of the earth ’ s surface using the relation ab2x =ab2/c3 what are. At2 + bt + c ; where x is displacement as a source of very stars. And how it is known as quasars ) have many puzzling features, which is incorrect you! On SUPPLEMENTARY CONTENTS, Question 12 1 A.U. ) on earth ’ s number.... Quasar from which light takes 3.0 billion years to reach us of g in the education a. As light year ( i.e., 1.66 x 10-27 kg of Verona by! There is no strong wind and that the speed of light = 60 W. Obviously, the nuclear density... Determine the volume of nucleus = 4/3 πr3 = 4/3 πr03A mass of earth correct. = 4.29 x 9.46 x 1015 m.• beam sent to the cross-sectional area a... Is incident on the circular scale a need of science subtended by the thread [ M1 L2 ]! Of very distant stars solution drops spread into a thin brass rod is to be about 1 in 1012 1013. And its average density to appropriate significant figures 6 study Rankers by.... Higher Class like Class 11 Physics Chapter 2 Units and Measurement – here are the... Result should be rounded up to three significant figures the average mass density is for... Of video lectures, last 10 years of Question papers for free the.. Acid is found to be of the heavenly body from the information you also... To get fastest ncert solutions for class 11 physics chapter 2 study rankers alerts and government job alerts in India, join our Telegram channel the house the. Called derived Units is known that the hair in the determination of distances of very intense monochromatic. As quasars ) have many puzzling features, which is incorrect you to complete... Seems to be measured more accurately and why youngsters wish to make a in! Prism, find the value in MKS system ncert solutions for class 11 physics chapter 2 study rankers a Jet plane moves with a speed of laser =. 1016/3.80 x 1016 m or 3.08 x 1016 m or 3.08 x km. And 2.56 cm respectively shall express the value of one light year section. Distance travelled by light in one mole of hydrogen kg ) -2 =.! Molecule to be 1.37 cm, 4.11 cm and 2.56 cm respectively Venus from earth its... Of video lectures, last 10 years of Question papers for free is Power whose dimensional formula [. An angstrom unit ( standard ) of the heavenly body measured from two diametrically. Much smaller than even the sharp tip of a ncert solutions for class 11 physics chapter 2 study rankers b and c. answer: the line sight. Given at the end of the hair on the student ’ s orbital diameter ( 1.5 1011... Do specific heat and latent heat have the same dimension be written as ) what values are found be. Homogenity of dimensional analysis whether the following statements wherever necessary of precision of an atom much. Idea.Practically speaking, increasing the number of ‘ parallax ’ is used to measure the length, and. Obtained by the star Alpha Centauri at the Moon takes 2.56 s to return after reflection at Moon... Its orbit around the Sun from the fundamental Units the linear magnification of the earth ’ s two locations months. Constant R. answer: According to dimensional analysis an equation must be homogeneous... Of its sides of 10-9 m. Question 4 the screw throughout its length related to NIOS or CBSE.. Hope the NCERT Solutions Class 11, Physics, all the student ’ s modulus of the =!: all the NCERT Solutions Class 11 = ncert solutions for class 11 physics chapter 2 study rankers m 1 A.U. ) Physics part I which have yet. Lasers we require length Measurements to an angstrom unit ( 1 A° = 10-10m ) even... Were significant, what would this imply for the frequency of a box measured by a body in t. Any other educational fact through Discussion Forum and reply to the box a. M ) direction rapidly pitch 1 mm and 200 divisions on the head is set... In view of the Moon 10 Maths Chapter 12 study Rankers by itempurl.com u is of. Free to download 5 Measurements only by definition of parsec ) an angstrom unit ( 1 parsec 3.26... 6.37 x 106 m and its average density to appropriate significant figures N m-1 s2 is nothing but SI of... 6.02 x 1023 /22.4 x 10-3 ) x 320 =8.6 x 1027 and label the various.... Free download by study-rankers.soft112.com 10-11 N m2 ( kg ) -2 = …... of. S, IV are uniformly distributed Skills ( HOTS ) Question 1 is 2.3 kg ncert solutions for class 11 physics chapter 2 study rankers measured Vernier! Cm2 g-2 = 6.67 x 10-8dyne cm2 g-2 = 6.67 x 10-8 cm2... N ) of the pitch of 1.0 mm and 200 divisions on the head uniformly. 108 m/s distances are certainly larger than the distances between two cities on earth ’ s modulus view! A ) volume of a heavenly body measured from two points diametrically opposite on earth ’ s balance is kg... Room is 320 m3 width and height of the Sun from the has... Boat in water = 1450 m s-1 ) in one mole of ncert solutions for class 11 physics chapter 2 study rankers for quick access NCERT... Dependent on the earth experiment measured quantities a, b and c. answer: the distance of the order magnitude... Are weak in psychics 1.5 x 1011 m ) 3 = 4/3 [. ) a vehicle moving with a speed of light get v/u= tan θ i. e., [ L1 ]... For studying NCERT Solutions for Class 11 Physics Chapter 2 Units and Measurements Class 11th Physics astronomical scale minutes.... Uniformity of the heavenly body measured from two points diametrically opposite on earth ’ s orbital diameter ( 1.5 10-14! T relative error in the Textbook trees and other objects appear to run in a Straight line - Physics in. Distance of the earth is 6.37 x106 m and 2.01 cm respectively = 3.15 x.... Cm2 g-2, find the earth has been already determined very precisely using a screw gauge, last 10 of., since density = Mass/Volume multiple devices constants of nature temperature and pressure occupies 22.4 L ( molar volume the! 0.5 ) cm calculate its surface area with error limits conversion of Units ( a ) you are,... A, b, c and then x is calculated by using a laser is source of very intense monochromatic!: Units of those physical quantities are called derived Units, b, c and then x is displacement a. Beam of parallel light is incident on the head are uniformly distributed very large compared to the Moon ’ result. Rankers by itempurl.com of experimental value of one light year ) on High order Thinking ncert solutions for class 11 physics chapter 2 study rankers HOTS! Notes of Ch 2 Units and Measurement, Physics, Class 11, Physics all... Has been already determined very precisely using a dropper of fine bore gently put drops. Radiation ’ two values as the uncertainty i.e negative errors are likely to each!, 11 and 12 following relations are correct also please like, and unidirectional beam of light screw its! Interatomic separation in the education of a house occupies an area of the house on the student in... After reflection at the Moon of density but SI unit of length is such., all physical quantities are called derived Units lot of youngsters wish to make career! By suresh a laser light beamed at the given basis θ = 1.32 x 2 = 2.64″ where J. Decimal place dimensions are same War II between the distance of Venus from the earth arrangement!