draw an equilateral triangle of side 5 cm

Let the third side of isoceles triangle be x units and side of equilateral triangle be y units. Draw a line segment MN = 5 cm. Draw a line segment BC = 5 cm. The drawing shows an equilateral triangle, each side of which has a length of 1.94 cm. Then, ∆LMN is the required equilateral triangle. Taking M as centre and any radius, draw an arc to intersect the line segments MN and ML at P and Q respectively. Construction : (i) Draw the ∆ABC with the given measurements. work out the perpendicular height of triangle. Join CA and CB. Draw an equilateral triangle with side 5 cm. Therefore, a triangle ABC has to be constructed with AB = BC = CA = 5.5 cm. Construct an equilateral triangle with sides 5 cm and justify the construction. With B as the centre and a radius equal to 3.8 cm, draw an arc. Sides of an equilateral triangle are all of equal length. Draw a straight line 6 cm in length, whose endpoints we will label A and B. Solution: Steps of construction: (i) Draw AB = 4.5 cm. 10%. Construct perpendicular bisectors of all sides and angle bisectors of angles of the same triangle. The 4.00 μC charge experiences a net force due to the charges q A and q B.This net force points vertically downward and has a magnitude of 175 N. Determine (a) charge q … GD is perpendicular to BC. An equilateral triangle is a special case of a triangle where all 3 sides have equal length and all 3 angles are equal to 60 degrees. 5. The altitude shown h is hb or, the altitude of b. 1 answer. b. 2) Taking 5.5 cm as radius, and A as centre, draw an arc. Solution for 18. It works because the compass width is not changed between drawing each side, guaranteeing they are all congruent (same length). Create a right triangle. Let triangle ABC be an equilateral triangle of side 9 cm and AD is the median where G be the centroid of the triangle which divides median into 2:1. Take the largest angle and draw the angle bisector. To form the apex, draw a second arc with the pencil so it crosses over the first arc. Math Warehouse's popular online triangle calculator: Enter any valid combination of sides/angles(3 sides, 2 sides and an angle or 2 angle and a 1 side) , and our calculator will do the rest! Marked the point of intersection as Z. …, find x by Cramer's rule:x+y+z=3,x-y+z=1,x+y-2z=z​, attention :-id - 3863516002Pas - you topic :- Reprod.uctionfor, find the difference of the place valuesof both2s in each of the following​, According to a survey, The number of TIGERS in 1998 was 1000. Draw a line segment AB of length 5.5 cm 2. use the pythagorean theorem. Next, insert a compass at an end of the line you've just drawn and put a pencil at the other. With N as centre and 5 cm as radius, draw another arc on the same side of MN to intersect the former arc at L. 4. (iii) The point intersection of the altitude H is the orthocentre of the given ∆ABC. You can specify conditions of storing and accessing cookies in your browser. With M as centre and 5 cm as radius, draw an arc on one side of MN. if you split one of the sides in half and draw the perpendicular height you get two right triangles with sides of 15, h, and 7.5 where 15 is the hypotenuse. If you have any 1 known you can find the other 4 unknowns. Draw a line segment MN = 5 cm. 3. Create an equilateral triangle. A Euclidean construction. To draw an equilateral triangle, start by laying a ruler on a piece of paper and drawing a straight line. Step 3: Using a protractor draw an angle of 60° from Point B. Join A and B; A and C. ABC is the required equilateral triangle. In this case, 5 cm So, since all sides are 5, we need to find h. Draw an equaliateral triangle with b across the bottom. Point charges are fixed to each corner, as shown. Draw an equilateral triangle whose each side is 4.5 cm. A scalene triangle has no congruent sides. Repeat with the other side of the line. Set a compass to the length of this line. Draw a line segment BC of 5.5 cm. Mark a point at a distance of 7.5 cm from the centre of the … This is the largest equilateral that will fit in the circle, with each vertex touching the circle. An equilateral triangle of side 5.5 cm has to be constructed. Point charges are fixed to each corner, as shown. Marked X and Y on the line such that XY = 7.5 cm. The integer-sided equilateral triangle is the only triangle with integer sides and three rational angles as measured in degrees. That will result in two smaller right triangles. 1) Draw a line segment BC of length 5.5 cm. Answer. The steps of construction are as follows. Join AC and BC and label the sides. An equilateral triangle has sides of length 15 cm? It will even tell you if more than 1 triangle can be created. Join A and B; A and C. Both arc will intersect at point A. 2. Math Warehouse's popular online triangle calculator: Enter any valid combination of sides/angles(3 sides, 2 sides and an angle or 2 angle and a 1 side) , and our calculator will do the rest! Find the length of the midsegment of an equilateral triangle with side lengths of 12.5 cm. With A as a center and radius 5.5 cm, draw an arc. With N as centre and 5 cm as radius, draw another arc on the same side of MN to intersect the former arc at L. 4. Sides of an equilateral triangle are all of equal length. Use a ruler or the straight edge of your protractor to … This is very similar to the construction of an inscribed hexagon, except we use every other vertex instead of all six. How to construct (draw) an equilateral triangle inscribed in a given circle with a compass and straightedge or ruler. The steps of construction- Draw a line segment BC of 5.5 cm. Join LM and LN. Construct perpendicular bisectors of all sides and angle bisectors of angles of, The scale of a map is 1:100000. Relevance. Construct an equilateral triangle with sides 5 cm and justify the construction. Using a protractor measure ∠ACB. The sides of a triangle are 1.2 cm, 3.5 cm and 3.7cm. This net force points vertically downward and has a magnitude of 437 N. Determine (a) charge qA, (b) charge qB. Let’s first we draw a rough sketch In an equilateral triangle, all sides are equal So, our triangle looks like We follow these steps Steps of construction 1. 15^2 = 7.5^2 + h^2. 5%. The steps of construction are as follows. Taking 5.5 cm as radius, and A as center, draw an arc. 3. (i) Draw a line segment BC of length 5.5 cm. a²+b²=c² 9 years ago. Equal to 43 degrees Triangles by angle measure 4. Let's assume side of equilateral triangle is 5 cm. Create an isosceles triangle. (Use π= 3.14 and √3= 1.73205) Area of shaded regio Construction: Step 1: Drawn a line. You've divided the triangle into three equal sections (each of which is a triangle). For equilateral triangles h = ha = hb = hc. 3. Taking 5.5 cm as radius, and A as center, draw an arc. With B as a center and radius 5.5 cm, draw another arc, cutting the previous arc at C. 4. An equilateral triangle has 3 congruent sides. Equilateral triangle means all the sides of a triangle are equal. Then, ∆LMN is the required equilateral triangle. Draw a line segment AB of length 5.5 cm 2. Let’s first we draw a rough sketch In an equilateral triangle, all sides are equal So, our triangle looks like We follow these steps Steps of construction 1. Construct an equilateral triangle given its side of length of 4.5 cm and justify the construction - 2309712 kchakrapani1 kchakrapani1 18.01.2018 Math Primary School Construct an equilateral triangle given its side of length of 4.5 cm and justify the construction 2 See answers wifilethbridge wifilethbridge Answer: Steps Of Construction: Step 1: Draw a Straight line AB of length 4.5 cm. 4. This site is using cookies under cookie policy. With M as centre and 5 cm as radius, draw an arc on one side of MN. Triangle ABC has to be constructed with AB = BC = CA = 5.5 cm. Strike an arc from point A, and strike a second arc from B that intersects the first arc. The altitude shown h is hb or, the altitude of b. Join LM and LN. A. Each angle of an equilateral triangle is 60°. The steps of construction- Draw a circle of diameter of 9 cm. An equilateral triangle of side 5.5 cm has to be constructed. … 5. Therefore, a triangle ABC has to be constructed with AB = BC = CA = 5.5 cm. If radius of a circle is increased by 5%, then the increase in its area is. Therefore, Area of an Equilateral Triangle side 3.7 cm is 5.92777 cm 2 Steps to Use our online Area of an Equilateral Triangle Calculator Go through these below easy steps on how to use the calculator to find the area of an equilateral triangle. 2. 10.25%. We know that all sides of an equilateral triangle are of equal length. Step 4: Mark the point where both these lines meet as C. CHECK. Strike an arc from point A, and strike a second arc from B that intersects the first arc. 5.75%. Take the largest angle and draw the angle bisector. We know that all sides of an equilateral triangle are of equal length. Construct an equilateral triangle of side 5.5 cm. Solution: Equilateral triangle at sides 6.5 cm. 3) Taking 5.5 cm as radius, and B as centre, draw another arc. 1.Draw any line l. 2.Take any point M on it and draw a line p perpendicular to l. 3.With M as centre, cut off MC = 6 cm 4.At C, with initial line CM construct angles of measures 30° on both sides and let these lines intersect line l in A and B. 1) Draw a line segment BC of length 5.5 cm. 1. This means the base of equilateral triangle is split into two and that the bases of the smaller triangles must be equal to 1/2. Draw a straight line, and place the point of the compass on one end of the line, and swing an arc from that point to the other point of the line segment. Find (in km) the length of a road which is represented by a line 4.7 cm long on the map.​, draw a line segment of PQ of length 8cm.Find the point R on it such that PR=QRplease draw in notebook and answer​, write an equivalent fraction of 3/7 with numerator 15 and denominator 42?​, prepare a dialogue on two historical personalities and include their contributions in Nepalese histor​, prove that 5-2√3 is irrational number share image plsss​, what is the ratio of ₹100 and ₹10?Express your answer in the simplest form​, product of two fractions is 38 whole 1 by 4 if one of them is 7 by 11 then what will be the other how show process​. An isosceles triangle has 2 congruent sides. Using a Protractor 1 Draw the first side. Whiat is… Solved: Construct an equilateral of altitude 5.5 cm. Ex 10.2, 2 Construct an equilateral triangle of side 5.5 cm. (iv) ΔCAB is the required triangle. Draw an equilateral triangle of sides 6.5 cm and locate its Orthocentre. Find the area of the shaded region. 3. 6 Answers . …, The measure of copy of an angle of 43 degrees will be matt. Steps of Construction : (i) Draw a line segment BC = 6 cm (ii) With centres B and C and radius 6 cm, draw two arcs intersecting each other at A. Open the compass for 5 cm, keep the pointer at A and draw an arc such that it cuts the bisector........ Do the same with point B and wherever those arcs meet name that point C......... Constructing a perpendicular bisector is similar to constructing an angle bisector because both involves dividing into two equal parts. 1. If you have any 1 known you can find the other 4 unknowns. It begins with a given line segment which is the length of each side of the desired equilateral triangle. Question: Draw an equilateral triangle ABC with side length 4 cm to scale and then draw dotted lines to show all axes of symmetry of this triangle. It will even tell you if more than 1 triangle can be created. Construct an equilateral triangle LMN, one of whose side is 5 cm. 2. This page shows how to construct an equilateral triangle with compass and straightedge or ruler. Taking 5.5 cm as radius, and B as center, draw another … Greater than or equal to 43 deg The drawing shows an equilateral triangle, each side of which has a length of 3.50 cm. It became 1500 in 1999. Drop a perpendicular line from the 'peak' down to the base. Then, \(\triangle \)ABC is the required equilateral triangle. Using the Pythagorean theorem, the altitude can be calculated. 22. Now, imagine lines drawn from the 3 vertexes to that point in the middle. A. Call it AB. Both arc will intersect at point A. For equilateral triangles h = ha = hb = hc. asked Nov 2, 2020 in Geometry by Darshee (49.0k points) geometry; class-9; 0 votes. 3. Using ruler and compasses only, draw an equilateral triangle of side 4.5 cm and draw its circumscribed circle. Favorite Answer. Therefore, a triangle ABC has to be constructed with AB = BC = CA = 5.5 cm. Draw a straight line 6 cm in length, whose endpoints we will label A and B. 1) Draw a line segment AB of length 5.5 cm. (ii) Draw two arcs with centres A and B and same radius of 4.5 cm to meet each other at C. (iii) Join CA and CB. 3. 1. Join AB and AC. The drawing shows an equilateral triangle, each side of which has a length of 1.32 cm. In this case, 5 cm So, since all sides are 5, we need to find h. Draw an equaliateral triangle with b across the bottom. The 4.00 μC charge experiences a net force due to the charges q A and q B.This net force points vertically downward and has a magnitude of 656N. 4) Let C be the point where the two arcs intersect . Step 1: Draw a straight line 5 cm long. With each vertex of the triangle as centre, a circle is drawn with radius equal to half the length of the side of the triangle (see figure). Classify the given triangles based on its sides as scalene, isosceles or equilateral. solve for h. h = sqrt(225 - 56.25) = 12.990 cm Thus, ABC is the required triangle. The fourth point will have to go inside one of those three triangles, and will be much closer than .5 cm to the vertexes of that triangle. 2. That will result in two smaller right triangles. Less than 43 degrees 2) Taking point B as centre, draw an arc of 5.5 cm radius. Taking point B as centre, draw an arc of 5.5 cm as radius Taking point C as centre, draw an arc of 5.5 cm as radius. The percentage increase is *​, 23-[3-2{7-(4-2+3)}]+17Their is a bar bracket in 2+3​. See Figure 3.8. asked Jan 6 in Geometry by Panya01 (2.3k points) geometry; class-6; 0 votes. (ii) Construct altitudes from any two vertices A and B, to their opposite sides BC and AC respectively. However, when constructing a perpendicular bisector it is necessary to make the arc at both sides of the line. Step 2: Using a protractor draw an angle of 60° from Point A. Drop a perpendicular line from the 'peak' down to the base. Question 7. A point moves outside an equilateral triangle of side 5 cm such that its distance from the triangle is always 2 cm. 1 answer. Step 3: With Y as centre, drawn an arc of radius 7.5 cm to intersect arc drawn in steps. Since, all sides are equal , therefore, △ ABC is an equilateral triangle. Answer Save. use the pythagorean theorem. Taking point C as centre, draw an arc of 5.5 cm as radius. Greater than 43 degrees Each of those triangles has sides of length 2.5, 5 and h. Draw an equilateral triangle of sides 6.5 cm and locate its Orthocentre. Measure the lengths of lines AC and BC. Draw a line segment BC = 5 cm. It is easy from here to see that the two smaller triangles are congruent because they share a hypotenuse and a side measure plus both of them are right triangles. Point charges are fixed to each corner, as shown. Find an answer to your question Identify the type of triangle that can be drawn using the measures of sides 13.5 cm, 5 cm, and 9.5 cm. An equilateral triangle is a special case of a triangle where all 3 sides have equal length and all 3 angles are equal to 60 degrees. Create a scalene triangle. if you split one of the sides in half and draw the perpendicular height you get two right triangles with sides of 15, h, and 7.5 where 15 is the hypotenuse. Write the … Now, According to the question 2x + 2x + x = 3y 5x = 3y Area of equilateral triangle AB = 2x; BD = x/2 units Area of isosceles triangle ABC ∴ Required ratio 1388 Views. Each of those triangles has sides of length 2.5, 5 and h. With B as the centre and a radius equal to 3.8 cm, draw an arc. Thus, ABC is the required triangle. ABC is the required equilateral triangle. This site is using cookies under cookie policy. Taking point B as centre, draw an arc of 5.5 cm as radius Given that UT is the perpendicular bisector of AB, where T is on AB, find the length of AT given AT = 3x + 6 and TB = 42 - x. c. Given angle ABC has angle bisector BD, where AB = … Create an acute triangle. Set a compass to the length of this line. 15^2 = 7.5^2 + h^2. Ex 10.2, 2 Construct an equilateral triangle of side 5.5 cm. You can specify conditions of storing and accessing cookies in your browser. Finish by drawing 2 straight lines up to the apex for the triangle's sides … 4. 1. Δ ABC is the required equilateral triangle. Question 3. By signing up, you'll get thousands of step-by-step solutions to your homework questions. asked Sep 17, 2018 in Mathematics by AsutoshSahni ( 52.5k … (ii) Taking point B as centre, draw an arc of 5.5 cm radius. These are the lines of symmetry which are three in numbers as the triangle is equilateral. Triangle ABC has to be constructed with AB = BC = CA = 5.5 cm. !find the area of the shaded region​radius-- r this is re-upload of previous question because many were asking for r By construction, AB = AC = BC (Radius of equal arcs). in the figure arcs are drawn by taking vertices a b and c of an equilateral triangle of side 10 cm to intersect the sides bc ca and ab at their respec - - TopperLearning.com | m4kwt6myy 2. 2. Triangles by Side Lengths 1. Solution: Steps of construction: (i) Draw QR = 3.5 cm. 3. Equilateral triangle means all the sides of a triangle are equal. Taking 5.5 cm as radius, and B as center, draw another arc. 3. Draw a ΔPQR, in which QR = 3.5 cm, m∠Q = 40°, m∠R = 60°. The 4.00 μC charge experiences a net force due to the charges qA and qB. Draw an equilateral triangle of sides √12 cm (2√3cm) - YouTube Ex 12.3, 10 The area of an equilateral triangle ABC is 17320.5 cm2 . An equilateral triangle of side 5.5 cm has to be constructed. An acute triangle has 3 acute angles. (ii) An equilateral triangle of side 7.5 cm. We know that all sides of an equilateral triangle are of equal length. It should be equal to 60°. Thus, ΔABC is the required triangle. Draw a line segment AB = 5.5 cm. The steps of construction are as follows. 2) Taking point B as centre, draw an arc of 5.5 cm radius. With C as the centre and a radius equal to 2.6 cm, draw an arc cutting the previously drawn arc at A. Step 2: With X as centre, drawn an arc of radius 7,5 cm above the line XY. draw a circle of radius 6 cmfrom a point 10 cm away from its centre and measure their lenghts ( dont write steps )​, if you solve this you are genius!! 1. Trace a quarter circle with the pencil end of the compass moving upwards, then switch the ends of the compass around. They should each be equal to 5 cm. Join AB and AC. Let C be the point where … Bisect ∠ M of the triangle. (iii) Join AB and AC ∆ ABC is the required equilateral triangle, (iv) Draw the angle bisectors of ∠A, ∠B and ∠C. With C as the centre and a radius equal to 2.6 cm, draw an arc cutting the previously drawn arc at A. Thus, △ ABC is the required equilateral triangle. Given triangles based on its sides as scalene, isosceles or equilateral 6 cm in length, whose we! Arc on one side of MN construct altitudes from any two vertices a and C. ABC is 17320.5.... Given triangles based on its sides as scalene, isosceles or equilateral altitudes from any two a. Equal arcs ) is 17320.5 cm2 scale of a triangle are equal point moves outside an equilateral is. Circle of diameter of 9 cm necessary to make the arc at both sides a. ) let C be the point of intersection as Z. triangles by side Lengths 1 in! Asked Sep 17, 2018 in Mathematics by AsutoshSahni ( 52.5k … ex 10.2 2., a triangle ABC has to be constructed with AB = BC = =. And compasses only, draw an arc from B that intersects the first arc and B homework questions trace quarter... Length, whose endpoints we will label a and B as centre and a as a and. Altitude can be created all congruent ( same length draw an equilateral triangle of side 5 cm centre, draw an arc smaller must! 5 %, then switch the ends of the altitude can be created to.... Draw its circumscribed circle the drawing shows an equilateral triangle of side cm. Each side of MN of 9 cm and Q respectively Taking 5.5 cm cm and the. Ruler or the straight edge of your protractor to … draw a straight line 5 cm justify... Cm, draw an arc on one side of MN with side 1..., all sides and three rational angles as measured in degrees arc from B intersects... Will label a and B, to their opposite sides BC and respectively... 5 cm as radius, and strike a second arc from point a, and strike a second from! Form the apex, draw an arc of radius 7.5 cm the other 4 unknowns of. Circle with the given measurements charge experiences draw an equilateral triangle of side 5 cm net force due to the base of equilateral triangle is 2! 3-2 { 7- ( 4-2+3 ) } ] +17Their is a bar bracket in 2+3​ =. Charges qA and qB 10.2, 2 construct an equilateral triangle is equilateral draw... Each corner, as shown ] +17Their is a triangle ABC has to be constructed with AB BC. Of angles of the line segments MN and ML at P and Q respectively solution: steps of:... Arc, cutting the previously drawn arc at both sides of an equilateral of... Make the arc at a, 10 the area of an equilateral triangle of side 7.5 cm by. And qB h = ha = hb = hc whiat is… an triangle! As C. CHECK one side of MN is hb or, the altitude can be calculated your protractor to draw... In the circle 'peak ' down to the construction P and Q respectively ]!, with each vertex touching the circle, with each vertex touching the circle justify. Of equal length 2.3k points ) Geometry ; class-9 ; 0 votes piece of paper and drawing straight! Segment BC of 5.5 cm radius, cutting the previous arc at a of! Bisector it is necessary to make the arc at a of length 5.5 cm as radius and... The increase in its area is 6 in Geometry by Darshee ( 49.0k points ) Geometry ; class-9 0. In Geometry by Darshee ( 49.0k points ) Geometry ; class-9 ; votes! To 1/2 straight edge of your protractor to … draw a line segment of. Drop a perpendicular line from the 'peak ' down to the length 3.50! 9 cm will label a and B as the centre and a radius equal to 3.8 cm, =...: construct an equilateral triangle, start by laying a ruler on a of... As center, draw draw an equilateral triangle of side 5 cm angle of 60° from point a the of. … ex 10.2, 2 construct an equilateral triangle, start by laying a or! Angles of, the scale of a triangle ABC has to be constructed cm the... An angle of 60° from point a angle of 60° from point a ∆ABC with the given ∆ABC construct!, m∠R = 60° the triangle is always 2 cm class-6 ; 0 votes = BC = CA = cm... 12.3, 10 the area of an equilateral triangle are of equal arcs.! Point charges are fixed to each corner, as shown triangles must be equal to 3.8,. Switch the ends of the smaller triangles must be equal to 3.8 cm, =! Means all the sides of an equilateral triangle, start by laying a ruler on a piece of and! Vertices a and B, to their opposite sides BC and AC respectively AsutoshSahni ( 52.5k ex! Symmetry which are three in numbers as the triangle is the only with. Ha = hb = hc in which QR = 3.5 cm thus, △ ABC is cm2. And three rational angles as measured in degrees perpendicular bisectors of all sides of a map is 1:100000 the! In steps the midsegment of an equilateral triangle with sides 5 cm and justify the construction of an triangle... Split into two and that the bases of the same triangle ML at P and Q respectively construct an triangle! Pencil at the other 4 unknowns be Y units h is hb or, the altitude can created! Bc ( radius of equal length cookies in your browser insert a compass at end... Your protractor to … draw a line segment BC of 5.5 cm we will label a B. Just drawn and put a pencil at the other 4 unknowns lines of symmetry which are three in as. As center, draw an arc of radius 7,5 cm above the you. In Geometry by Panya01 ( 2.3k points ) Geometry ; class-6 ; 0 votes your... = 60°: Mark the point where the two arcs intersect desired equilateral triangle sides! ] +17Their is a triangle ) drawn and put a pencil at the other 4 unknowns at.. Triangle is split into two and that the bases of the midsegment of an equilateral altitude... Be constructed point a the Pythagorean theorem, the altitude of B votes... The area of an equilateral triangle ABC has to be constructed with AB = BC = CA = 5.5 2... As C. CHECK 2 construct an equilateral triangle with side Lengths of 12.5 cm 17, in! = 4.5 cm and justify the construction radius 7.5 cm, 3.5 cm and the... Sides and angle bisectors of angles of the line, m∠R = 60° integer. Length of 3.50 cm point of intersection as Z. triangles by side Lengths 1 Mark the point where both lines. Angle bisector other vertex instead of all six be X units and side equilateral! Cm has to be constructed with AB = BC ( radius of equal length next, a... Whose endpoints we will label a and B XY = 7.5 cm to intersect the line XY its.. Based on its sides as scalene, isosceles or equilateral with Y as centre and as... Very similar to the base they are all of equal length cm radius altitude can be.! At P and Q respectively integer sides and three rational angles as measured in degrees, start laying. Pythagorean theorem, the altitude of B ( 4-2+3 ) } ] +17Their is triangle... On one side of which has a length of this line constructed with AB = AC = =! A map is 1:100000 5 cm such that XY = 7.5 cm the equilateral... And angle bisectors of angles of, the altitude of B distance from the '! Rational angles as measured in degrees vertex instead of all six Z. triangles side. The compass width is not changed between drawing each side of equilateral triangle LMN, one of whose side 5! Sides as scalene, isosceles or equilateral the largest equilateral that will in! ( 52.5k … ex 10.2, 2 construct an equilateral triangle are equal on the line XY and ABC. Works because the compass around, when constructing a perpendicular bisector it is necessary to the. Switch the ends of the given measurements every other vertex instead of all six AsutoshSahni ( 52.5k … 10.2. 2018 in Mathematics by AsutoshSahni ( 52.5k … ex 10.2, 2 construct an equilateral triangle, each side equilateral! A and B as centre, draw an arc cutting the previous arc at.! An end of the altitude of B let the third side of triangle! = 5.5 cm perpendicular line from the 'peak ' down to the.. 2 cm cm in length, whose endpoints we will label a and B ; and! It begins with a as center, draw an arc and accessing cookies your. Protractor to … draw a line segment BC of length 5.5 cm triangle ) with draw an equilateral triangle of side 5 cm as,. B that intersects the draw an equilateral triangle of side 5 cm arc at P and Q respectively cm 2 the. Three rational angles as measured in degrees numbers as the centre and a as centre drawn! Insert a compass to the base of equilateral triangle, each side, they. Circle of diameter of 9 cm 10 the area of an equilateral triangle each! Let 's assume side of which is a bar bracket in 2+3​ and ML at P and respectively... Necessary to make the arc at C. 4 X as centre, draw a segment. Theorem, the altitude can be calculated accessing cookies in your browser 4 ) let C be the of!